c4countdown

Bobby Banerjee is up to 6 wins, and is as of right now the number one seed in the series (out of two winners). It's never certain whether 6 is enough for the finals though, so a 7th might be good. Can he do it?

Join Callum for the recap later.

Apterite alert!

Yay! An apterite - should be a good one.

who is it you bastards

Ciaran Crawley.

Also, alternate second numbers, roundabout for a different reason: (50/2)x ((8x4) + 5 -2)

37x25 was my way to make 875 (same as Jordan) or you can make that a 1750/2 solution.

As everyone knows FUMAROLE is the anagram of FORMULAE to avoid showing your paper.

And what a boring 3L!

Tony Atkins wrote:As everyone knows FUMAROLE is the anagram of FORMULAE to avoid showing your paper.

(Actually I didn't know)

Well done to Ciaran for getting the first win for apterous in the new year, a very solid effort. Unlucky for Bobby, hopefully the 6 wins are going to be enough for the finals, a solid effort for him through his few games.

I gave a lot of advice to Ciaran when he knew he was on - seems to have paid off.

One of our other Ciarans is recording in February so there are a lot of them about this series.

Solid debut - thought Bobby was sticking round for 8 wins, but that was fairly comfortable really. Some pretty decent spots here and there.

Well done Ciaran. I thought Bobby would struggle against someone who'd had some practice, and so it proved, but he was very pleasant and gracious in defeat, which is nice to see.

GENITORS/TRIGONES in round 1, AMULET in round 2 and INWALES/NEMESIA in round 13.

2nd Numbers Alt.: ((((50 + 4) x 2) + 2) x 8) - 5 = 875

Just DORKIER made me miss a max game today, ah well.

Let's hope for a good run from Ciarán (nice that they even added the accent on his nameplate too. )