c4countdown

!4x!4-sqrt!4-sqrt!4=75 !4x!4-sqrt!4-sqrt4=76 !4x!4-sqrt4-sqrt4=77 I'm not sure these are valid under the rule on concatenation. Can somebody clarify this? No problem with any of these. Concatenation mean running two 4s together to make 44. Thanks Howard, thought it might have meant use of brackets.

!4x!4-sqrt!4-sqrt!4=75
!4x!4-sqrt!4-sqrt4=76
!4x!4-sqrt4-sqrt4=77
I'm not sure these are valid under the rule on concatenation.
Can somebody clarify this?

My apologies Daniel

Innis Carson wrote:

Daniel O'Dowd wrote:
(!4)

What function is this? Looks pretty helpful.

I think he means .4 recurring[uhttp://en.wikipedia.org/wiki/Recurring_decimal#Notationrl][/url]
in which case 4!+4+(4/.4recurring)=37

Howard Somerset wrote:

Liam Tiernan wrote: 44-(4/.4)=37

No. This makes 34.

As I see it, the missing ones are now:
37, 39, and 51 onwards.

Oops. Still can't see 37.
And hadn't noticed that I'd skipped 39.

4!+4+4+sqrt4=34
4!+(44/4)=35
4!+4+4+4=36
44-(4/.4)=37
44-4-sqrt4=38
44-sqrt4-sqrt4=40
44-4+(4/4)=41
44-4=sqrt4=42
44-(4/4)=43
44-4=4=44
44=(4/4)=45
44+4-sqrt4=46
4!+4!-(4/4)=47
4!+4!=4-4=48
4!+4!+(4/4)=49
4!+4!+(4/sqrt4)=50

Next one..........not so easy.

Next one's easy (4*4)+(4*4)=32

4!+4+4-4=28 4!+4+(4/4)=29 4!+4+(4/sqrt4)=30

4!+4-(4/4)=27

((44/4)*sqrt4)+4=26

(44+4)/sqrt4=24

((4!*4)-4)/4=23

4!-4-4+4=20 4!-4 +(4/4)=21 4*4+4+sqrt4=22

4*4 +(4 /sqrt4 )=18 4!-4-(4/4)=19

Pulled it back though with two great spots in AMNESTY and SENSIBLE.

1st rd. LARVAE for six? Not a max but still enough to win the round.

You can add my name to the list for the u1000.

How about a bonus point as in rugby for a certain margin of victory (say 25 or 30 points), rather than just a century?